scratchfoundation/paper.js
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Fix some comments.

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Jürg Lehni 2013-05-26 17:48:36 -07:00
parent 7050edd6e4
commit 32709a176b
1 changed files with 6 additions and 6 deletions
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12
src/path/Curve.js
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@ -1308,12 +1308,12 @@ new function() { // Scope for methods that require numerical integration
p3 = [ 1, dq3 ]; p3 = [ 1, dq3 ];
// Check if p1 and p2 are on the same side of the line [ p0, p3 ] // Check if p1 and p2 are on the same side of the line [ p0, p3 ]
if (distq1 * distq2 < 0) { if (distq1 * distq2 < 0) {
// dq1 and dq2 lie on different sides on [ p0, p3 ]. The hull is // dq1 and dq2 lie on different sides of [ p0, p3 ]. The hull is
// a quadrilateral and line [0, q0, 1, q3] is NOT part of the hull // a quadrilateral and line [ p0, p3 ] is NOT part of the hull so we
// so we are pretty much done here. // are pretty much done here.
return [ p0, p1, p3, p2 ]; return [ p0, p1, p3, p2 ];
} }
// dq1 and dq2 lie on the same sides on [ p0, p3 ]. The hull can be // dq1 and dq2 lie on the same sides of [ p0, p3 ]. The hull can be
// a triangle or a quadrilateral and line [ p0, p3 ] is part of the // a triangle or a quadrilateral and line [ p0, p3 ] is part of the
// hull. Check if the hull is a triangle or a quadrilateral. // hull. Check if the hull is a triangle or a quadrilateral.
var pmax, cross; var pmax, cross;
@ -1332,8 +1332,8 @@ new function() { // Scope for methods that require numerical integration
cross = (dq1 - dq0 + (dq0 - dq3) / 3) cross = (dq1 - dq0 + (dq0 - dq3) / 3)
* (-2 * (dq0 - dq1) + dq0 - dq2) / 3; * (-2 * (dq0 - dq1) + dq0 - dq2) / 3;
} }
// Compare cross products of these vectors to determine, if // Compare cross products of these vectors to determine if the point is
// point is in triangles [ p3, pmax, p0 ] or [ p0, pmax, p3 ] // in the triangle [ p3, pmax, p0 ], or if it is a quadrilateral.
return cross < 0 return cross < 0
// p2 is inside the triangle, hull is a triangle. // p2 is inside the triangle, hull is a triangle.
? [ p0, pmax, p3 ] ? [ p0, pmax, p3 ]